ps2sol - Homework 2 Solutions October 10, 2007 A 1.83...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
Homework 2 Solutions October 10, 2007 A 1.83 Consider a force balance in the x direction of a cylindrical section of jet: D = 12 mm F W = force on flat face in positive x direction due to other half of cylinder = Δ pA = Δ plD F T = force in negative x direction due to surface tension on sides of cylinder = σ w (2 l ) * We neglect surface tension on the top and bottom edges under the assumption that the jet is long ( l >> D ). Δ pA = 2 w Δ p = 2 σ w D = (2)(0 . 078 N/m) 0 . 012 m = 12 . 1 Pa 1
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
1.86 Consider a force balance in the z direction of a steel rod floating on the surface: F W = force in the negative z direction due to weight of rod = γ steel V rod = γ steel ( lπD 2 4 ) F T = force in the positive z direction due to surface tension = σ W (2 l ) * Assume again that l >> D and neglect surface tension at the ends of the rod. σ w (2 l ) = γ steel lπD 2 4 D = q 8 σ w γ steel π = 0 . 0051 ft = 0 . 061 in 2.13 The pipes are horizontal and the fluid in them is continuous, so we expect the average pressure at either piston to be the same.
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 5

ps2sol - Homework 2 Solutions October 10, 2007 A 1.83...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online