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Unformatted text preview: 108 MHz. Recall that the ±ourier Transform of cos(2 πf t ) yields two impulses, one at frequencyf Hz (or equivalently at2 πf rad/sec), and the other at frequency f Hz. When x c ( t ) is sampled, it creates replicas of X c ( f ) with a separation of f s . Thus, we will have impulses atf + kf s and at f + kf s , for each integer (both negative and positive) k . So, we are interested in identifying those f for which eitherf + kf s or f + kf s is inside 88108 MHz for some integer k . Then, it can be seen that there are 3 bands in the 250 MHz to 1000 MHz region that will alias into the 88 MHz to 108 MHz ±M band: (a) 392412 MHz  or 2 π 3922 π 412 rad/sec (b) 588608 MHz  or 2 π 5882 π 608 rad/sec (c) 892912 MHz  or 2 π 8922 π 912 rad/sec 1 Problem 3 2...
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 Spring '10
 Staff
 Frequency, Hertz, MHz, 2412 rad, 2608 rad

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