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Unformatted text preview: -108 MHz. Recall that the ourier Transform of cos(2 f t ) yields two impulses, one at frequency-f Hz (or equivalently at-2 f rad/sec), and the other at frequency f Hz. When x c ( t ) is sampled, it creates replicas of X c ( f ) with a separation of f s . Thus, we will have impulses at-f + kf s and at f + kf s , for each integer (both negative and positive) k . So, we are interested in identifying those f for which either-f + kf s or f + kf s is inside 88-108 MHz for some integer k . Then, it can be seen that there are 3 bands in the 250 MHz to 1000 MHz region that will alias into the 88 MHz to 108 MHz M band: (a) 392-412 MHz - or 2 392-2 412 rad/sec (b) 588-608 MHz - or 2 588-2 608 rad/sec (c) 892-912 MHz - or 2 892-2 912 rad/sec 1 Problem 3 2...
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- Spring '10