329fall09hw1sol - ECE 329 Homework #1 Solution Fall 2009 1....

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ECE 329 Homework #1 Solution Fall 2009 1. a) D = A + B = 4 b x + 2 b y- 3 b z b) A + B- 4 C = 4 b x + 2 b y- 3 b z- 4 ( b x- 2 b y + 3 b z ) = 10 b y- 15 b z c) | A + B- 4 C | = 10 2 + 15 2 = 18 . 03 d) A + 2 B- C = (3 b x + b y- 2 b z ) + 2 ( b x + b y- b z )- ( b x- 2 b y + 3 b z ) = 4 b x + 5 b y- 7 b z | A + 2B- C | = 4 2 + 5 2 + 7 2 = 9 . 49 u = A + 2B- C | A + 2B- C | = 4 b x + 5 b y- 7 b z 9 . 49 = 0 . 42 b x + 0 . 53 b y- . 74 b z e) A B = (3 b x + b y- 2 b z ) ( b x + b y- b z ) = 3 1 + 1 1 + (- 2) (- 1) = 6 f) B C = ( b x + b y- b z ) ( b x- 2 b y + 3 b z ) = b x ( b x- 2 b y + 3 b z ) + b y ( b x- 2 b y + 3 b z )- b z ( b x- 2 b y +3 b z ) = (- 2 b z- 3 b y ) + (- b z + 3 b x )- ( b y + 2 b x ) = b x- 4 b y- 3 b z 2. In the three cases, we have the same E and B at the origin, but di erent v . Thus, we have di erent F . In each case, v and F must satisfy F = q ( E + v B ) . Therefore, we have the following three equations: 3 b z = E...
View Full Document

This note was uploaded on 05/05/2010 for the course ECE 329 taught by Professor Franke during the Spring '08 term at University of Illinois at Urbana–Champaign.

Page1 / 2

329fall09hw1sol - ECE 329 Homework #1 Solution Fall 2009 1....

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online