{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

# lec3 - 2.001 MECHANICS AND MATERIALS I Lecture#3 Prof Carol...

This preview shows pages 1–7. Sign up to view the full content.

2.001 - MECHANICS AND MATERIALS I Lecture #3 9/13/2006 Prof. Carol Livermore Recall from last time: FBD: Solve equations of motion. M A = 0 F x = 0 F y = 0 See 9/11/06 Notes. Solution: 1

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Draw each component separately. FBD of Bar 1 F x = 0 F A x + F C x = 0 F y = 0 F A y + F C y = 0 M A = 0 l cos θF C y l sin θF C x = 0 Solve. F A x = F C x F A y = F C y F C y sin θ = = tan θ Forces track with angle. F C x cos θ Two Force Member: If forces are only applied at 2 points, then: 1. Forces are equal and opposite. 2. Forces are aligned (colinear) with the vector tha connects the two points of application of forces. So the FBD could be rewritten as: 2
Now look at the FBDs of 1, 2, and C: Solve equations of equilibrium for Pin C. F x = 0 P + F 2 sin φ F 1 sin φ = 0 F y = 0 F 2 cos φ F 1 cos φ = 0 F 1 = F 2 M = 0 No additional info.(Γ = 0) P + 2 F 2 sin φ = 0 Note φ = 30 , so: F 2 = P F 1 = P Now look at FBD of 1, 2, and A: 3

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Look at equilibrium of Pin A: F X = 0 P cos θ + F 3 = 0 F 3 = P cos θ Note θ = 60 , so: P F 3 = 2 So: EXAMPLE: 4
Q: What are the reactions at the supports? FBD: F x

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 7

lec3 - 2.001 MECHANICS AND MATERIALS I Lecture#3 Prof Carol...

This preview shows document pages 1 - 7. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online