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lecture04 - CS 143 Lecture 4 1 I mplementation of Lexical...

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Unformatted text preview: CS 143 Lecture 4 1 I mplementation of Lexical Analysis Lecture 4 CS 143 Lecture 4 2 Tips on Building Lar ge Systems • KI SS (Keep I t Simple, Stupid!) • Don’t optimize prematurely • Design systems that can be tested • I t is easier to modify a working system than to get a system working CS 143 Lecture 4 3 Outline • Specifying lexical structure using regular expressions • Finite automata – Deterministic Finite Automata (DFAs) – Non-deterministic Finite Automata (NFAs) • I mplementation of regular expressions RegExp => NFA => DFA => Tables CS 143 Lecture 4 4 N otation • There is variation in regular expression notation • Union: A | B ≡ A + B • Option: A + ε ≡ A? • Range: ‘a’+’b’+…+’z’ ≡ [a-z] • Excluded range: complement of [a-z] ≡ [^ a-z] CS 143 Lecture 4 5 Regular Expr essions in Lexical Specification • Last lecture: a specification for the predicate s ∈ L(R) • But a yes/ no answer is not enough! • I nstead: partition the input into tokens • We adapt regular expressions to this goal CS 143 Lecture 4 6 Regular Expr essions => Lexical Spec. (1) 1. Write a rexp for the lexemes of each token • Number = digit + • Keyword = ‘if’ + ‘else’ + … • I dentifier = letter (letter + digit)* • OpenPar = ‘(‘ • … CS 143 Lecture 4 7 Regular Expr essions => Lexical Spec. (2) 1. Construct R , matching all lexemes for all tokens R = Keyword + I dentifier + Number + … = R 1 + R 2 + … CS 143 Lecture 4 8 Regular Expr essions => Lexical Spec. (3) 1. Let input be x 1 …x n For 1 ≤ i ≤ n check x 1 …x i ∈ L(R) 1. I f success, then we know that x 1 …x i ∈ L(R j ) for some j 1. Remove x 1 …x i from input and go to (3) CS 143...
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lecture04 - CS 143 Lecture 4 1 I mplementation of Lexical...

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