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exam 1 key #1 spring 2010

# exam 1 key #1 spring 2010 - Problem 1 The standard free...

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Problem 1: The standard free energy for phosphate hydrolysis of two compounds are: G’° (kJ/mol) ATP ADP + P i -30.5 glucose-6-phosphate glucose + P i 13.8 A. (6pts) If the actual concentrations of ATP, ADP and P i are 2.25 X 10 -3 M, 0.25 X 10 -3 M, and 1.65 X 10 -3 M, respectively, will ATP hydrolysis (ATP ADP + P i ) be spontaneous at room temperature (25 °C) under these conditions? Why? (Please write the equation you use and show all work.) G’ = G’° + RT ln ([ADP][Pi]/[ATP]) 1 pt for Q, 1 pt for the equation G‘= -30.5 kJ/mol + (0.008314 kJ/mol)(298 K) ln (0.25 X 10 -3 )(1.65 X 10 -3 )/ (2.25 X 10 -3 ) G’ = -30.5 kJ/mol + (-21.3 kJ/mol) G’ = -51.8 kJ/mol 1pt for correct number, 1pt for unit The negative G’ indicates that the reaction is spontaneous for ATP break down. 2pts B. (3pts) Will glucose-6-phosphate be hydrolyzed down more quickly (increased rate) or more slowly (decreased rate) than ATP? Why? Don’t know. There is no rate information given by thermodynamic values.

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exam 1 key #1 spring 2010 - Problem 1 The standard free...

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