quiz 9 key spring 2010

quiz 9 key spring 2010 - NADH to Ubiquinone in complex I...

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Quiz 9- Key 1. 6 points Write the overall balanced chemical equation for the oxidation of one molecule of acetyl CoA via the citrate cycle. Identify the starting substrates, products, and the electron carriers. AcetylCoA + 3 NAD+ + FAD + GDP + Pi +H 2 O -> 2CO 2 + 3 NADH + FADH 2 + GTP + 2H + + CoA Starting: AcetylCoA, GDP, Pi (required) NAD+ and FAD Products: Co 2 , GTP, CoA (required), NADH and FADH 2 (can be in listed as electron carrier) Electron carriers: NAD+/NADH and FADH 2 2. 4 points Use the appropriate standard reduction potentials listed below to calculate the change in reduction potential ( Δ E 0 ') when electrons flow from
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Unformatted text preview: NADH to Ubiquinone in complex I. Show your work. Half reaction E ' (V) 1/2 O 2 + 2H+ + 2 e- ----> H 2 O +0.816 NO 3 + 2H+ + 2 e- ---> NO 2 + H 2 O +0.421 Ubiquinone ox + 2 e- ---> Ubiquinone red +0.10 FAD + 2H+ + 2 e- ---> FADH 2-0.219 NAD+ + 2H+ + 2 e- ---> NADH -0.320 Δ E º' = ( E º' e-acceptor ) − ( E º' e-donor ) = E º' ubiquinone- E º' NADH = 0.10V – (-.320V) = 0.42V or NADH + Ubiquinone ox-> NAD+ Ubiquinone red In half reactions NADH -> NAD+ + 2H+ + 2e- E ’= + 0.32 V (must switch the sign) Ubiquinone 0x + 2e- -> Ubiquinone red E ’ = +0.10 V E ’ = 0.42 V...
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This note was uploaded on 05/06/2010 for the course BIOC 460 taught by Professor Ziegler during the Spring '07 term at Arizona.

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quiz 9 key spring 2010 - NADH to Ubiquinone in complex I...

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