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Unformatted text preview: Project : Gas Dynamics ID : 1000711176 Name : Krushit Shah Complition Tmac.m Project : Gas Dynamics ID : 1000711176 Name : Krushit Shah Final Solution Project : Gas Dynamics ID : 1000711176 Name : Krushit Shah Solution Solution Project : Gas Dynamics ID : 1000711176 Name : Krushit Shah Step 1 From theta bita Minf relation we find the value of theta For bita = 50 & Minf = 5, Theta = 35 Step 2 For Mach no M Mn1 = Minf*sin(bita) Mn1 = 3.8 from the Table A2 for Normal shock M = 4.407 Step 3 After getting the theta & M we find Vprime = [ 2/(gamma1)*M^2]^1/2 Vprime = 0.8917 Step 4 From geometry of fig we find the Vprimer = 0.5731. As shown in fig the Vtheta component is opposite from the Vr vector so take the Vtheta is Negative Vprime(theta) = 0.1502 Project : Gas Dynamics ID : 1000711176 Name : Krushit Shah...
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 Spring '10
 luca

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