159E1-F2009

159E1-F2009 - MA 15900 1 Solve the equation 3 5 EXAM 1 1 x...

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MA 15900 EXAM 1 FALL 2009 1 1. Solve the equation. 3 5 + x = 4 7 1 7 x 1) x = 17 42 2) x = 17 42 3) x = 1 6 4) x = 1 6 5) x = 21 4 6) x = 21 4 7) x = 1 4 8) x = 1 4 9) None of the above 2. Express as a polynomial. ( x + y ) 2 ( x y ) 2 1) x 2 y 2 2) x 2 + y 2 3) x 2 2 xy + y 2 4) x 2 + 2 xy + y 2 5) x 2 4 x xy 2 xy 4 y xy + y 2 6) x 2 4 x xy + 2 xy 4 y xy + y 2 7) x 2 + 4 x xy 2 xy + 4 y xy + y 2 8) x 2 + 4 x xy + 2 xy + 4 y xy + y 2 9) None of the above 3. Solve for x . Find all solutions. x 3 + 8 x 2 + 17 x = 0 1) x = 0 2) x = 4 3) x = 8 4) x = 4 ± 2 i 5) x = 4 ± i 6) x = 8 ± i 7) x = 0, 4 ± 2 i 8) x = 0, 4 ± i 9) x = 0, 8 ± i
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MA 15900 EXAM 1 FALL 2009 2 4. Simplify the expression. 4 x 2 9 2 x 2 + 7 x + 6 ÷ 8 x 7 27 x 4 4 x 4 + 6 x 3 + 9 x 2 1) x + 2 x 2 (2 x 3) 2 2) ( x + 2)(2 x + x 2 (2 x 2 3) (4 x 2 + 6 x + 9)( x + 2)(2 x + x 2 (2 x 2 4) (4 x 2 + 6 x + 9)( x + 2) x 2 (2 x 2 5) 4 x 2 + 6 x + 9 x 2 (2 x 3)( x + 2) 6) 4 x 2 + 6 x + 9 x 2 (2 x + 3)( x + 2) 7) 1 x 2 ( x + 2) 8) 1 x 2 (2 x + 3)( x + 2) 9) None of the above 5. Simplify the expression. 16 x 9 y 3 x 0 y 1 2 1) 256 x 18 y 8 2) 256 x 18 y 7 3) 256 x 18 y 6 4) 256 x 18 y 4 5) 256 x 11 y 8 6) 256 x 11 y 7 7) 256 x 11 y 6 8) 256 x 11 y 4 9) None of the above
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MA 15900 EXAM 1 FALL 2009 3 6. Simplify the expression, and rationalize the denominator when appropriate.
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This document was uploaded on 05/07/2010.

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159E1-F2009 - MA 15900 1 Solve the equation 3 5 EXAM 1 1 x...

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