MA266 prac_ex1 - 1 A solution of dy 2y = with y(1 = 8 is dt t 1 A y =(t 1)2 4 B y = 32(t 1)2 C y = 2(t 1)2 D y = 4 E y = 2(t 1(t 1)2 60 2x is y x2

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1. A solution of dy dt = 2 y t + 1 with y (1) = 8 is A. y = ( t + 1) 2 + 4 B. y = 32( t + 1) - 2 C. y = 2 ( t + 1) 2 D. y = 4 p 2( t + 1) E. y = p ( t + 1) 2 + 60 2. An implicit solution of y 0 = 2 x y + x 2 y is A. y 2 = 2 ln(1 + x 2 ) + C B. y 2 = C ln(1 + x 2 ) C. 1 2 y 2 = ln x 2 + C D. y 2 = ln(1 + x 2 ) + C E. 1 2 y 2 = ln | 1 + x | + C 3. The substitution v = y/x transforms the equation dy dx = sin( y/x ) into A. v 0 = sin( v ) B. v 0 = x sin( v ) C. v 0 + v = sin( v ) D. xv 0 + v = sin( v ) E. v 0 + xv = sin( v ) 4. The solution in implicit form of dy dx = x 2 + 3 y 2 2 xy is: A. x 2 + y 2 = x 3 + C B. x 2 + y 2 = Cx 3 C. x 2 + x 3 = y 2 + C D. Cx 2 = x 3 + y 2 E. x 2 + y 3 + xy 2 = C 5. Which of the following best describes the stability of equilibrium solutions for the au- tonomous differential equation y 0 = y (4 - y 2 )? A. y = 0 unstable; y = 2 and y = - 2 both stable 1
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B. y = 0 unstable; y = 2 stable C. y = 0 and y = 2 both stable D. y = 0 stable; y = 2 unstable; y = - 2 stable E. y = 0 stable;
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This note was uploaded on 05/08/2010 for the course MA 266 taught by Professor Multi during the Spring '05 term at Purdue University-West Lafayette.

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MA266 prac_ex1 - 1 A solution of dy 2y = with y(1 = 8 is dt t 1 A y =(t 1)2 4 B y = 32(t 1)2 C y = 2(t 1)2 D y = 4 E y = 2(t 1(t 1)2 60 2x is y x2

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