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Unformatted text preview: Could I see a solution to this? 28) F=qE ma=qE E=ma/q=9.11x10^-31/(-1.6x10^-19)x1.80x10^9i=***-1.02 x 10^-2i N/C*** 38) The minimum difference between measured values in the table is 1.6 x 10^-19, therefore this is the charge of the electron. 46) initial U=-p*E=-pE*cos theta Final U=-p*E=-pEcos(pi-theta)=pEcos theta Work=Ufinal-Uinitial=PE*cos theta-(-PE*cos theta)=2PE*cos theta...
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This note was uploaded on 05/09/2010 for the course MGMT e33 taught by Professor Allansmith during the Spring '10 term at Aarhus Universitet, Aarhus.
- Spring '10