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Exam 1 Answer 1 - Problem 1 33 points The floor system...

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Unformatted text preview: Problem 1: 33 points The floor system shown below is used in a light storage warehouse. In addition to the live load, the floor carries 6” of cinder concrete. Twelve foot (12’) tall walls of unplastered 2x4’s run along members AI, BJ, and DK; these roads are treated as dead loads. Internal members are placed at regular intervals, which implies that you can use symmetry to determine beam-to-beam and girder-to-girder distances, Where required. All corner members frame directly into columns. Using a basic load case of 1.2D+1.6L, determine the factored load on members AD and AI. Dead ’. Floor azmv’fi [2404»! = (57-4 “32931265 7.59 (Wmfl ‘5 + FL) '2‘! t3 ' ‘3 3 = 41499 a {+3990 #720914. = ‘Hfis? (A, L Laws! 2'17“) Ila, I w 26990 l _%_ B C 12.0 T to“; = 24mg x so =13 29 “1+ 47} =- Zb‘tfofi/‘(M‘ 97ch(-'E')+E¢nzo ({1} '—S 3, 392 Hz ...
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