Fall07_Test_3_Solution_Key

Fall07_Test_3_Solution_Key - 1 PGE 312 - FALL 2007 Physical...

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1 PGE 312 - FALL 2007 Physical and Chemical Behavior of Petroleum Fluids I Test 3 Solution Key 1. ( 20 points ) Your company has discovered a dry gas reservoir with the following characteristics: Reservoir area = 2 miles x 1 mile Reservoir thickness = 250 ft Initial reservoir pressure = 5000 psia Reservoir temperature = 200 ° F Average porosity = 15% Average water saturation = 20% Initial gas Z-factor = 1.01 Calculate the initial gas in place in standard cubic feet. Note: 1 mile = 5280 feet Solution to Problem 1 (2*5280*1*5280)(250)(0.15)(1 0.20) res cu ft 1.01*(200 460) res cu ft 0.02827 5000 scf g gi gi Ah S HCPV G B B φ = = - = + = 9 3 1.673 10 3.769 10 x scf x - = 4.438x10 11 scf
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2 2. ( 15 points ) Figure 1 shows the production performance of a dry gas reservoir with no water influx. Solution to Problem 2 a. Determine the initial gas in place in standard cubic feet (scf). From the graph, G = 1.120x10 9 scf b. Predict the gas recovery factor in % if the gas field will be abandoned at a P/ Z of 2000 psia. At abandonment, Gpa = 8.0x10 8 scf Gas Recovery Factor = (Gpa/G)100 = (8.0x10 8 / 1.120x10 9 ) = 71.4% P/Z vs Gp Plot 0 1000 2000
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This note was uploaded on 05/09/2010 for the course PGE fluids taught by Professor Peters during the Spring '10 term at University of Texas at Austin.

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Fall07_Test_3_Solution_Key - 1 PGE 312 - FALL 2007 Physical...

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