Ch%2015_p1

Ch%2015_p1 - Optimal Machine Replacement with the Weibull...

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Unformatted text preview: Optimal Machine Replacement with the Weibull Distribution Page 1 Determining optimal Chapter 15 Problem 1 replacement policy Cost per hour of down time $200.00 Cost of replacement $5,000.00 Hours for planned replacement 2 Hours for unplanned replacement 20 Weibull alpha 6 Weibull beta 60 Total Cost Planned replacement interval #ADDIN? Totals #ADDIN? #ADDIN? #ADDIN? Down-Time Replacement Down-time Time Next Failure Next planned replacement Over 1K hours? Hours Cost Cost #ADDIN? 100 1 #ADDIN? 5000 #ADDIN?Simulation Results for ch 15_p1.XLS #ADDIN? #ADDIN? #ADDIN? #ADDIN? #ADDIN? #ADDIN? #ADDIN? #ADDIN? #ADDIN? #ADDIN? #ADDIN? #ADDIN? #ADDIN? #ADDIN?Iterations= 100 #ADDIN? #ADDIN? #ADDIN? #ADDIN? #ADDIN? #ADDIN? #ADDIN?Simulations= 5 #ADDIN? #ADDIN? #ADDIN? #ADDIN? #ADDIN? #ADDIN? #ADDIN?# Input Variables= 48 #ADDIN? #ADDIN? #ADDIN? #ADDIN? #ADDIN? #ADDIN? #ADDIN?# Output Variables= 1 #ADDIN? #ADDIN? #ADDIN? #ADDIN? #ADDIN? #ADDIN? #ADDIN?Sampling Type= Latin Hypercube #ADDIN? #ADDIN? #ADDIN?#ADDIN?...
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