Ch%2015_p1 - Optimal Machine Replacement with the Weibull...

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Optimal Machine Replacement with the Weibull DistributionPage 1Determining optimalChapter 15 Problem 1replacement policyCost per hour of down time$200.00 Cost of replacement$5,000.00 Hours for planned replacement2Hours for unplanned replacement20Weibull alpha6Weibull beta60Total CostPlanned replacement interval#ADDIN? Totals#ADDIN?#ADDIN?#ADDIN?Down-TimeReplacementDown-timeTimeNext FailureNext planned replacementOver 1K hours?HoursCostCost0#ADDIN?1001#ADDIN?5000#ADDIN? Simulation Results for ch 15_p1.XLS#ADDIN?#ADDIN?#ADDIN?#ADDIN?#ADDIN?#ADDIN?#ADDIN?#ADDIN?#ADDIN?#ADDIN?#ADDIN?#ADDIN?#ADDIN?#ADDIN? Iterations= 100#ADDIN?#ADDIN?#ADDIN?#ADDIN?#ADDIN?#ADDIN?#ADDIN? Simulations= 5#ADDIN?#ADDIN?#ADDIN?#ADDIN?#ADDIN?#ADDIN?#ADDIN? # Input Variables= 48#ADDIN?#ADDIN?#ADDIN?#ADDIN?#ADDIN?#ADDIN?#ADDIN? # Output Variables= 1#ADDIN?#ADDIN?#ADDIN?#ADDIN?#ADDIN?#ADDIN?#ADDIN? Sampling Type= Latin Hypercube#ADDIN?#ADDIN?#ADDIN?#ADDIN?#ADDIN?#ADDIN?#ADDIN? Runtime= 00:00:27#ADDIN?#ADDIN?#ADDIN?#ADDIN?#ADDIN?#ADDIN?#ADDIN?

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