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# hw 33 - homework 33 HETTIGER CHRISTOF Due 4:00 am Question...

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homework 33 – HETTIGER, CHRISTOF – Due: Apr 19 2008, 4:00 am 2 = (3 kg) (9 . 8 m / s 2 ) (24 m / s) 2 = 0 . 0510417 kg / m . The velocity is v 2 = radicalBigg F μ , so v 1 = radicalbigg m 2 g μ (2) = radicalBigg (2 . 7 kg) (9 . 8 m / s 2 ) 0 . 0510417 kg / m = 22 . 7684 m / s . AlternateSolution: Plugging μ from Eq. 1 into Eq. 2, we have v 1 = radicalbigg m 2 g μ (2) = radicalBigg m 2 g v 2 1 m 1 g = v 1 radicalbigg m 2 m 1 (3) = (24 m / s) radicalBigg (2 . 7 kg) (3 kg) = 22 . 7684 m / s . Question 4, chap 16, sect 2. part 1 of 3 10 points A sonar signal of frequency 1 . 76 × 10 6 Hz has a wavelength of 1 . 84 mm in water.
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