{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

# hw 31 - homework 31 HETTIGER CHRISTOF Due 4:00 am Question...

This preview shows pages 1–3. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
homework 31 – HETTIGER, CHRISTOF – Due: Apr 15 2008, 4:00 am 2 For minimum period, ℓ T dℓ = 0, so - R 2 2 g 2 + 1 g = 0 2 = R 2 2 = R 2 = 1 . 5 m 2 = 1 . 06066 m . Question 3, chap 15, sect 5. part 3 of 3 10 points What will be the period at this distance? Correct answer: 2 . 92179 s (tolerance ± 1 %). Explanation: T = 2 π radicaltp radicalvertex radicalvertex radicalvertex radicalvertex radicalbt 1 2 R 2 + 1 2 R 2 g R 2 = 2 π radicalBigg 2 R g = 2 π radicalBigg 2 (1 . 5 m) 9 . 81 m / s 2 = 2 . 92179 s .
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 5

hw 31 - homework 31 HETTIGER CHRISTOF Due 4:00 am Question...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online