eqtable3 - Equation Table: me 9.111031 kg 1eV 1.602 1019 J...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Equation Table: cm s kJ K hJ s h  300 10 138 10 6 626 10 2 8 23 34 . . . | 1 1 2 2 v c | 31 19 23 0 0 71 9.11 10 1 1.602 10 1 / 1.780 10 1240 0.0529 1.0973732 10 e mk g eV J MeV c kg hc eV nm an m R m  0 0 L L tt | ' ' ' ' 2 () x xu t yy zz u x c     | '' ' ' 2 x t u x c  | ' ' ' ' 2 x xut u x c      ' 2 , ' , 2 1 1 x x x yz x vu v c v v c | 2 22 2 2 2 m Em c KE mc mc Ec p m c  pv | 0 cu f f Eh f fc p | max 0 max Ke V Kh f ' 3 (1 cos ) 2.43 10 e C e h mc h nm   | 4 0 13.606 11 1 8 ε if n fi e hf E E hcR Ee V nn EE R hc n n me R hc  |  2 5/ 4 2 1 hc kT hc I e IT hh pm v
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
x y z xp yp zp Et    | 2 2 2 1 () dx xx d x f xf x d x    | 2 2 k f / 22 2 (, ,,) (, ,) 2 iEt xyzt xyze dx Ux Ex md x    2 2 2 s i n , 1 ,2 ,3 , ,1 , 2 , 3 , 28 2 1 ,0 , 1 , 2 , 3 , 2 n n n nx xn LL p h En n n mm L m L n    
Background image of page 2
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 05/10/2010 for the course PHYSICS 262 taught by Professor Paulso during the Spring '10 term at George Mason.

Page1 / 2

eqtable3 - Equation Table: me 9.111031 kg 1eV 1.602 1019 J...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online