ch10 - SOLUTIONS TO B EXERCISES E10-1B (15–20 minutes)...

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Unformatted text preview: SOLUTIONS TO B EXERCISES E10-1B (15–20 minutes) Item Land Land Improvements Building Other Accounts (a) ($357,500) Notes Payable (b) $357,500 (c) $ 10,400 (d) 9,100 (e) 7,800 (f) (1,300) (g) 28,600 (h) 325,000 (i) 11,700 (j) $ 5,200 (k) 14,300 (l) (6,500) (m) 16,900 (n) 24,700 (o) 18,200 (p) 3,900 E10-2B (10–15 minutes) The allocation of costs would be as follows: Land Building Land $80,000 Razing costs 8,400 Salvage (1,260) Legal fees 370 Survey $ 440 Plans 13,600 Title insurance 300 Liability insurance 180 Construction 548,000 Interest 34,000 $87,810 $596,220 10-1 E10-3B (10–15 minutes) 1. Truck #1.............................................................. 34,750.00 Cash........................................................... 34,750.00 2. Truck #2.............................................................. 37,407.55* Discount on Notes Payable.............................. 2,592.45 Cash........................................................... 5,000.00 Notes Payable........................................... 35,000.00 *PV of $35,000 @ 8% for 1 year = $35,000 X .92593= $32,407.55 $32,407.55 + $5,000.00 = $37,407.55 3. Truck #3.............................................................. 38,000.00 Cost of Goods Sold........................................... 30,000.00 Inventory.................................................... 30,000.00 Sales.......................................................... 38,000.00 [Note: The selling (retail) price of the computer system appears to be a better gauge of the fair value of the consideration given than is the list price of the truck as a gauge of the fair value of the consideration received (truck). Vehicles are very often sold at a price below the list price.] 4. Truck #4.............................................................. 26,000.00 Common Stock......................................... 10,000.00 Paid-in Capital in Excess of Par.............. 16,000.00 (1,000 shares X $26 = $26,000) 10-2 E10-4B (20–25 minutes) (a) Avoidable Interest Weighted-Average Accumulated Expenditures X Interest Rate = Avoidable Interest $1,000,000 15% $150,000 800,000 10.42% 83,360 $233,360 Weighted-average interest rate computation Principal Interest 10% short-term loan $ 700,000 $ 70,000 11% long-term loan 500,000 55,000 $1,200,000 $125,000 Total interest = $125,000 = 10.42% Total principal $1,200,000 (b) Actual Interest Construction loan $1,000,000 X 15% = $150,000 Short-term loan $700,000 X 10% = 70,000 Long-term loan $500,000 X 11% = 55,000 Total $275,000 Because avoidable interest in lower than actual interest, use avoidable interest. Cost $2,600,000 Interest capitalized 233,360 Total cost $2,833,360 Depreciation expense= $2,833,360 – $150,000 = $89,445 30 years 10-3 E10-5B (20–25 minutes) (a) Computation of Weighted-Average Accumulated Expenditures Expenditures Date Amount X Capitalization Period = Weighted-Average Accumulated Expenditures July 31 $300,000 3/12 $75,000 November 1 150,000 $75,000...
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This note was uploaded on 05/10/2010 for the course ACC 440 BSB1568 taught by Professor Warwick during the Spring '09 term at University of Phoenix.

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ch10 - SOLUTIONS TO B EXERCISES E10-1B (15–20 minutes)...

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