Ch3Sec6 - THE FIBER FORUM Fiber Optic Communications...

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THE FIBER FORUM Fiber Optic Communications JOSEPH C. PALAIS PRESENTED BY
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Joseph C. Palais 3.6 2 Section 3.6 Critical Angle Reflection Fresnel’s Law of Refraction i i i i s i i i i p n n n n n n n n n n n n n n θ ρ 2 2 1 2 2 1 2 2 1 2 2 1 2 2 1 2 2 1 2 2 2 2 1 2 2 1 2 2 sin cos sin cos sin cos sin cos - + - - = - + - + - = For parallel polarization: (3.29) (3.30) For perpendicular polarization:
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Joseph C. Palais 3.6 3 CRITICAL ANGLE REFLECTION From equations (3.29) and (3.30), we find that 2 2 2 2 1 1, 1 1 sin 0 p s i and thus R when n n ρ θ = = = - = n 1 sin θ i = n 2
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Joseph C. Palais 3.6 4 CRITICAL ANGLE REFLECTION 1 2 sin n n c = θ Call the solution θ c , the critical angle . θ c only exists if n 1 > n 2 . That is, travel from a high index to a low index material. This result is valid for both polarizations. (3.34) The incident angle satisfying this equation is the angle whose sine is given by:
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Joseph C. Palais 3.6 5 CRITICAL ANGLE REFLECTIONS i i i i c i n n n n n n n n θ 2 2 1 2 2 2 2 1 2 2 2 2 2 2 1 2 1 2 2 sin and 0 sin sin sin , - < -
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This note was uploaded on 05/11/2010 for the course EEE EEE-448 taught by Professor Palais during the Fall '09 term at ASU.

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Ch3Sec6 - THE FIBER FORUM Fiber Optic Communications...

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