HW1-Grading Policy

HW1-Grading Policy - 1.53 Using a Hub: Bandwidth that the...

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The full score will be 60 point. 1.46 Magnetic disk: Time for 1/2 revolution = 1/2 rev*1/7200 minutes/rev*60 seconds/minutes = 4.17 ms Time for 1/2 revolution = 1/2 rev*1/10,000 minutes/rev*60 seconds/minutes = 3 ms 1.47 (DVD): Bytes on center circle = 1.35 MB/seconds*1/1600 minutes/rev*60seconds/minutes = 50.6 KB Bytes on outside circle = 1.35 MB/seconds*1/570 minutes/rev*60seconds/minutes = 142.1 KB 1.48 Total requests bandwidth = 30 requests/sec*512 Kbit/request = 15,360 Kbit/sec < 100 Mbit/sec. Therefore, a 100 Mbit Ethernet link will be sufficient. 1.50 a. Propagation delay = m / s sec Transmission time = L / R sec End-to-end delay = m / s + L / R b. End-to-end delay = m / s + L / R + t c. End-to-end delay = m / s + 2 L /R + t /2 1.52 CISC time = P *8 T = 8 PT ns RISC time = 2 P *2 T = 4 PT ns RISC time = CISC time/2, so the RISC architecture has better performance.
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Unformatted text preview: 1.53 Using a Hub: Bandwidth that the other four computers consume = 2 Mbps*4 = 8 Mbps Bandwidth left for you = 10 8 = 2 Mbps Time needed = (10 MB*8 bits/byte) / 2 Mbps = 40 seconds Using a Switch: Bandwidth that the other four computers consume = 2 Mbps*4 = 8 Mbps Bandwidth left for you = 10 Mbps. The communication between the other computers will not disturb you! Time needed = (10 MB*8 bits/byte)/10 Mbps = 8 seconds 1.54 To calculate d = a * b a * c, the CPU will perform 2 multiplications and 1subtraction. Time needed = 10*2 + 1*1 = 21 nanoseconds. We can simply rewrite the equation as d = a * b a * c = a *( bc ). Then 1 multiplication and 1 subtraction will be performed. Time needed = 10 x 1 + 1 * 1 = 11 nanoseconds ....
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HW1-Grading Policy - 1.53 Using a Hub: Bandwidth that the...

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