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Unformatted text preview: 1.53 Using a Hub: Bandwidth that the other four computers consume = 2 Mbps*4 = 8 Mbps Bandwidth left for you = 10 8 = 2 Mbps Time needed = (10 MB*8 bits/byte) / 2 Mbps = 40 seconds Using a Switch: Bandwidth that the other four computers consume = 2 Mbps*4 = 8 Mbps Bandwidth left for you = 10 Mbps. The communication between the other computers will not disturb you! Time needed = (10 MB*8 bits/byte)/10 Mbps = 8 seconds 1.54 To calculate d = a * b a * c, the CPU will perform 2 multiplications and 1subtraction. Time needed = 10*2 + 1*1 = 21 nanoseconds. We can simply rewrite the equation as d = a * b a * c = a *( bc ). Then 1 multiplication and 1 subtraction will be performed. Time needed = 10 x 1 + 1 * 1 = 11 nanoseconds ....
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 Fall '08
 BaoxinLi

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