{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

# HW3-Grading Policy - 3.1 0000 0000 0000 0000 0001 0000 0000...

This preview shows pages 1–3. Sign up to view the full content.

3.1 0000 0000 0000 0000 0001 0000 0000 0000two 3.2 1111 1111 1111 1111 1111 1000 0000 0001two 3.9 The problem is that A_lower will be sign-extended and then added to \$t0. The solution is to adjust A_upper by adding 1 to it if the most significant bit of A_lower is a 1. As an example, consider 6-bit two’s complement and the address 23 = 010111. If we split it up, we notice that A_lower is 111 and will be signextended to 111111 = –1 during the arithmetic calculation. A_upper_adjusted = 011000 = 24 (we added 1 to 010 and the lower bits are all 0s). The calculation is then 24 + –1 = 23. 3.30 a. –1 391 460 350 b. 2 903 506 946 c. –8.18545 * 10 –12 d.sw \$s0, 2(\$t0) 3.42 a. Convert +1 . 1011 * 2 14 + –1 . 11 * 2 –2 1.1011 0000 0000 0000 0000 000 –0.0000 0000 0000 0001 1100 000 ----------------------------------------------------------- 1.1010 1111 1111 1110 0100 000 0100 0110 1101 0111 1111 1111 0010 0000 b. Calculate new exponent: + 111 11 1 + 100 0110 1 +011 1110 1 --------------------------- 1000 0101 0 –011 1111 1 minus bias 1111 1111 --------------------------------------------- 100 0101 1 new exponent Multiply significands: . 1.101 1000 0000 0000 0000 0000 * L L L L g v ( g v ( 1 1.110 0000 0000 0000 0000 0000 ----------------------------------------------------------------------------------- 1 11 11 1 1011 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 11 0110 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 + 1.10 1100 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
----------------------------------------------------------------------------------- 10.11 1101 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 Normalize and round: exponent 100 0110 0 significand 1.011 1010 0000 0000 0000 0000
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern