Quiz 5 - Version 131 – Quiz 5 – Laude – (52455) 1...

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Unformatted text preview: Version 131 – Quiz 5 – Laude – (52455) 1 This print-out should have 8 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. E o cell = E o cathode- E o anode E cell = E o cell- parenleftbigg . 05916 n parenrightbigg · log Q Q = [ C ] c · [ D ] d [ A ] a · [ B ] b Δ G o =- n · F · E o cell =- R · T · ln K E o cell = parenleftbigg R · T · ln K n · F parenrightbigg parenleftbigg I · t n · F parenrightbigg = moles of product Half reaction E o F 2 + 2 e −-→ 2 F − +2 . 87 Cl 2 + 2 e −-→ 2 Cl − +1 . 36 Na + + e −-→ Na- 2 . 71 Li + + e −-→ Li- 3 . 04 F = 96 , 485 . 3 C per moleof e − Ampere = 1 C · s − 1 R = 8 . 314 J · mol − 1 · K − 1 N = 6 . 022 × 10 23 001 5.0 points You construct a cell for which E = -0.4V. Which of the following statements about cell convention is not true? 1. The anode is positive. 2. Electrons flow through the external cir- cuit to the anode. correct 3. Oxidation occurs at the anode....
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This note was uploaded on 05/11/2010 for the course CH 302 taught by Professor Holcombe during the Spring '07 term at University of Texas.

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Quiz 5 - Version 131 – Quiz 5 – Laude – (52455) 1...

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