Dynamics_Part12

Hence we conclude that aa a i cos j sin 5 ai 4 5 ab

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Unformatted text preview: e conclude that aA = a(-i cos - j sin ) 5 ai 4 5 aB = aA + aB/A = a(-i cos - j sin ) + a i 4 Rearranging terms, we find 5 - cos a i - a sin j 4 Thus, since the velocity vector is vB = aB t, the speed at time t is aB = |vB | = at = at = at = at Therefore, Block B's speed at time t is |vB | = at 4 41 - 40 cos 5 - cos 4 2 + sin2 25 5 - cos + cos2 + sin2 16 2 25 5 - cos + 1 16 2 41 5 - cos 16 2 We are given a = 10 cm/sec2 and = 30o , what is |vB | when t = 5 sec. Substituting into the equation above, we have the following. 1 cm cm (5 sec) 41 - 40 cos 30o = 31.5 10 |vB | = 2 4 sec sec...
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