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When the particle strikes, the vehicle’s position is
x
A
=
L
+
V
2
nV
sin
α
g
+
1
4
g
w
2
nV
sin
α
g
W
2
Simplifying, we find
x
A
=
L
+
2
nV
2
sin
α
g
+
n
2
V
2
sin
2
α
g
So,
x
A
=
x
B
when
L
+
2
nV
2
sin
α
g
+
n
2
V
2
sin
2
α
g
=
2
n
2
V
2
sin
α
cos
α
g
which can be rearranged to yield
V
2
g
sin
α
(2 cos
α
−
sin
α
)
n
2
−
2
V
2
sin
α
g
n
−
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This note was uploaded on 05/12/2010 for the course AME 301 taught by Professor Shiflett during the Spring '06 term at USC.
 Spring '06
 Shiflett

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