Dynamics_Part32

Dynamics_Part32 - mgh } 1 3 2 o cot ] = 1 2 mv 2 Solving...

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So, the Principle of Work and Energy tells us that T 1 + U 1 2 = T 2 Denoting the crate’s velocity at the bottom of the ramp by v ,wehave T 1 =0 and T 2 = 1 2 mv 2 Thus, we conclude that
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Unformatted text preview: mgh } 1 3 2 o cot ] = 1 2 mv 2 Solving for the velocity yields v = 2 gh } 1 3 2 o cot ]...
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This note was uploaded on 05/12/2010 for the course AME 301 taught by Professor Shiflett during the Spring '06 term at USC.

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