Unformatted text preview: V II B and V I C , which is V II B = 1 2 (1 − e ) V I B and V I C = 1 2 (1 + e ) V I B Finally, we know from Part (b) that V I B = 1 2 (1 + e ) g f Therefore, the final solution for V II B and V I C is V II B = 1 4 (1 − e 2 ) g f and V I C = 1 4 (1 + e ) 2 g f (d) We now have all the information we need to compute the height to which Sphere C rises, f C , and thereby find the value of the coefficient of restitution for the observed value of f C . We know that total mechanical energy is conserved, the initial potential energy of Sphere C is zero and its final kinetic energy is zero. Thus, 1 2 mV I 2 C + 0 = 0 + mg f C = ⇒ f C = V I 2 C 2 g Substituting for V I C from Part (c), we have f C = (1 + e ) 4 16 g f 2 g = (1 + e ) 4 32 f...
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This note was uploaded on 05/12/2010 for the course AME 301 taught by Professor Shiflett during the Spring '06 term at USC.
 Spring '06
 Shiflett

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