Dynamics_Part38

Dynamics_Part38 - Solving this initial-value problem, we...

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Solving this initial-value problem, we find z = h + 0 2 gH t cos 2 β 1 2 gt 2 The ball strikes the ground for the first time when z =0 . Thus, h + 0 2 gH t cos 2 β 1 2 gt 2 =0 = t 2 2 ± 2 H g t cos 2 β 2 h g =0 Solving the quadratic and rejecting the physically irrelevant root with the minus sign before the radical, we have t = ± 2 H g ^ cos 2 β + 5 cos 2 2 β + h H ² Now, we are given
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This note was uploaded on 05/12/2010 for the course AME 301 taught by Professor Shiflett during the Spring '06 term at USC.

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