Dynamics_Part40

Dynamics_Part40 - v cos θ A straightforward algebraic...

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Similarly, subtracting the impact-relation equation from the momentum-conservation equation tells us that 2 v I Ax = 6 5 (1 e ) v (1 + e ) v cos θ = v I Ax = 3 5 (1 e ) v 1 2 (1 + e ) v cos θ Therefore, the puck velocity vectors after the impact are v I A = } 3 5 (1 e ) v 1 2 (1 + e ) v cos θ ] i v I B = } 3 5 (1 + e ) v 1 2 (1 e ) v cos θ ] i + v sin θ j (b) If puck A is at rest after the impact so that v I A = 0 , necessarily 3 5 (1 e ) v = 1 2 (1 + e
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Unformatted text preview: ) v cos θ A straightforward algebraic exercise shows that e = 6 − 5 cos θ 6 + 5 cos θ Finally, we are given cos θ = 6 35 . Hence, e = 6 − 5(6 / 35) 6 + 5(6 / 35 = 6 − 6 / 7 6 + 6 / 7 = 42 − 6 42 + 6 = 36 48 Therefore, the coefficient of restitution is e = 3 4...
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This note was uploaded on 05/12/2010 for the course AME 301 taught by Professor Shiflett during the Spring '06 term at USC.

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