Dynamics_Part46

Dynamics_Part46 - z ( t f ) = h , wherefore h = eV sin w eV...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Next, we use the fact that in order for the velocity vector to exactly horizontal, we must have v I z = ˙ z ( t f )=0 . Thus, we have ˙ z ( t f )= eV sin θ gt f =0 = eV sin θ = gL V cos θ Solving for L , there follows L = e V 2 g sin θ cos θ It is helpful to combine the equations for t f and L , which yields t f = eV g sin θ The ball’s height when it reaches the upper surface is
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: z ( t f ) = h , wherefore h = eV sin w eV g sin W 1 2 g w eV g sin W 2 Simplifying and combining like terms, the solution for h is h = 1 2 e 2 V 2 g sin 2...
View Full Document

Ask a homework question - tutors are online