Dynamics_Part64

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Unformatted text preview: . . .. . .. . .. .. . .. . .. .. . .. . ... . ... .. . ... .. . . ... . ... .. .. . ... .. . .. . ... . ... ... ... ... ... . ... ... . .... . . .... .... ... ... . .... ... ... . ...... . .. . .................... ................... . ................... . ............. . ... . ... . . .. . .. .. . . . . 1 . . . . . . v3.... . . . . v R R v 1 2 v 3 A B E v . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . ... . . ... . . .. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . E (a) Focusing first on expressing velocity vectors v1 , v2 and v3 relative to the center of gear A, we have the following. v1 v2 v3 = vA + A r1/A = vA + S r2/A = vA + E r3/A Since gear A is not translating, clearly vA = 0. Gears A and E are rotating clockwise and counter clockwise, respectively. We are given the following. 5 A = - k 4 and E = k...
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## This note was uploaded on 05/12/2010 for the course AME 301 taught by Professor Shiflett during the Spring '06 term at USC.

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