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Dynamics_Part74

Dynamics_Part74 - Therefore the angular-velocity vector is...

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Therefore, the angular-velocity vector is ω = H mR 2 i 0 . 002 H mR 2 ( i cot θ p csc θ ) = H mR 2 (1 0 . 002 cot θ ) i + 0 . 002 H mR 2 csc θ p Finally, the desired representation of the angular-velocity vector is ω = ω s i + ω p p , wherefore ω s = H mR 2 (1 0 . 002 cot θ ) and ω p = 0 . 002 H mR 2 csc θ (c) For the given values, the quantity H/ ( mR 2 ) is H mR 2 = 0 . 75 kg · m 2 / sec (30 kg)(0 . 05 m) 2 = 10 sec 1 Therefore, the x and y components of the angular velocity vector are as follows. ω x = H mR 2
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