Dynamics_Part81

Dynamics_Part81 - (c) For Block A, the equation of motion...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
(c) For Block A, the equation of motion is M ¨ x =2 T ±,²1 Cable Tension k ( x + x eq ) ± 1 Spring Force For Block B, the equation of motion is m ¨ y = mg ±,²1 Weight T ±,²1 Cable Tension and y x Therefore, the equations of motion for Blocks A and B are M ¨ x T k ( x + x eq )a n d2 m ¨ x = mg T (d) So, we can use Block B’s equation of motion to specify the cable-tension, viz., T = mg 2 m ¨ x Substituting this expression for T into Block A’s equation of motion tells us that
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 05/12/2010 for the course AME 301 taught by Professor Shiflett during the Spring '06 term at USC.

Ask a homework question - tutors are online