Dynamics_Part81 - (c) For Block A, the equation of motion...

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(c) For Block A, the equation of motion is M ¨ x =2 T ±,²1 Cable Tension k ( x + x eq ) ± 1 Spring Force For Block B, the equation of motion is m ¨ y = mg ±,²1 Weight T ±,²1 Cable Tension and y x Therefore, the equations of motion for Blocks A and B are M ¨ x T k ( x + x eq )a n d2 m ¨ x = mg T (d) So, we can use Block B’s equation of motion to specify the cable-tension, viz., T = mg 2 m ¨ x Substituting this expression for T into Block A’s equation of motion tells us that
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This note was uploaded on 05/12/2010 for the course AME 301 taught by Professor Shiflett during the Spring '06 term at USC.

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