{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}


Dynamics_Part81 - (c For Block A the equation of motion is...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
(c) For Block A, the equation of motion is M ¨ x =2 T ±,²1 Cable Tension k ( x + x eq ) ± 1 Spring Force For Block B, the equation of motion is m ¨ y = mg ±,²1 Weight T ±,²1 Cable Tension and y x Therefore, the equations of motion for Blocks A and B are M ¨ x T k ( x + x eq )a n d2 m ¨ x = mg T (d) So, we can use Block B’s equation of motion to specify the cable-tension, viz., T = mg 2 m ¨ x Substituting this expression for T into Block A’s equation of motion tells us that
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Ask a homework question - tutors are online