Homework Solution

# Homework Solution - S L< P Q where S = 14 L = 80 P =...

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ME350 F07 HW #2 Solution 2.

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3.

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4. For (a) M=6(L-1)-5J 1 -4J 2 -3J 3 -2J 4 -J 5 L=4 J 1 =2 J 2 =1 J 3 =1 Therefore, M=6(4-1)-5(2)-4(1)-3(1) = 1 For (b) M=6(L-1)-5J 1 -4J 2 -3J 3 -2J 4 -J 5 L=4 J 1 =1 J 2 =3 Therefore, M=6(4-1)-5(1)-4(3) = 1 5. The inversion is #1 where the slider (pistons) translates. The crank has a fixed length inside of the engine and as the cylinders rotate around in the engine, the pistons move in and out. Therefore, the pistons are translating in a linear motion up and down through the cylinder. Some students may have type II, which also is accepted.
6. Type 1 Kinematic Chain or Grashof crank rocker.
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Unformatted text preview: S+L < P+Q where S = 14, L = 80, P = 79.901, Q = 51.26 7 . a) Piston compression – piston moves up and down to compress air b) Gear compression – air passes through the gear to be compressed c) Scroll compressor – two vanes move in conjunction with each other. d) Rotary screw compressor – turbo in a car e) Axial flow compressor – turbine engine f) Centrifugal compressor – water pump g) Diagonal or mixed-flow compressors h) Membrane compressor Other solutions work here as well...
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## This note was uploaded on 05/12/2010 for the course MECHENG 350 taught by Professor Shih during the Winter '10 term at University of Michigan.

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Homework Solution - S L< P Q where S = 14 L = 80 P =...

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