ME 211 Homework 2 Solutions

9lbs cos30 45 3rb sin60 rb 1193lbs 40 ra

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Unformatted text preview: 25.98lbs Answers Problem#54.37 Thewindlassissubjectedtoaloadof150lbs.DeterminethehorizontalforceP neededtoholdthehandleinthepositionshown,andthex,y,zcomponentsof reactionattheballandsocketAandthesmoothjournalbearingB.Thebearingis inproperalignmentandexertsonlyforcereactionsontheshaft. 1.)DrawtheFBD 2.)Writetheequilibriumequationsandsolve.(Fx,Fy,andM)andsolveforP,Bz, Bx,Ax,Ay,andAz. M y = 0 = 150lbs * (0.5) - P(1) P = 75lbs M x = 0 = Bz * (4) -150(2) Bz = 75lbs M z = 0 = Bx * (4) - 75(6) Bx = 112.5lbs F F F x = 0 = AX + 75 -112.5 Answers = 0 = Ay = 0 = Az + 75 -150 Ax = 37.5lbs y Ay = 0 z Az = 75lbs Problem#64.60 DeterminethemaximumweightWthemancanliftwithconstantvelocityusingthe pulleysystem,withoutandthenwiththe"leadingblock"orpulleyatA.Theman hasaweightof200lbsandthecoefficientofstaticfrictionbetweenhisfeetandthe groundiss=0.6. 1.)DrawtheFBD Part(a) 2.)Writetheequilibriumequations.(Fx,Fy,andM)Noticetherearethree changesindirectionduetothepulleys,soyoucandividetheweightby3because thatishowmuchyouareactuallylifting.Alsonoticethatinpart(a)heispullingat a45degreeangle,soitwilltakemorework. W * cos(45) + 0.6N 3 W Fy = 0 = 3 sin(45) + N - 200 W = 318lbs F x =0=- Part(b) 3.)Withthenewpulley,youcanseethatthe...
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