ME 211 Homework 2 Solutions

Me 211 homework 2 solutions

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Unformatted text preview: Problem#14.5 ME211HomeworkSet#2Solutions 9192008 DeterminethemagnitudeofforceatthepinAandinthecableBCneededtosupport the500lbload.NeglecttheweightoftheboomAB. Solution 1.) DrawtheFreeBodyDiagram(FBD) 2.)Writetheequilibriumequations.Alwayswriteanequationthatsumstheforces inthexdirection,asummationoftheforcesintheydirection,andamoment equationaroundapointwhereyouwanttoeliminateanunknown.(Fx,Fy,and M) M A = 0 = 8 ft * FBC * sin(13) - 8 ft * 500lb * cos(35) F F x y = 0 = -500 * sin(35) - FBC * cos(13) + AX = 0 = -500 * cos(35) + FBC * sin(13) + Ay 3.)Withtheequationsabove,wenowhave3equationsand3unknowns,sowecan solveforallthreeunknowns(Ax,Ay,andFBC) M A = 0 = 8 ft * FBC * sin(13) - 8 ft * 500lb * cos(35) FBC = 1820.73lbs F F x = 0 = -500 * sin(35) - FBC * cos(13) + AX = 0 = -500 * cos(35) + FBC * sin(13) + Ay AX = 2060.91lbs y Ay = 0lbs 4.)Withtheseunknowns,youcansolveforthemagnitudeoftheforceatA,andthe magnitudeinBCisalreadysolvedforabove. MagnitudeA = (2060.912 + 0 2 = 2060.91lbs Answers MagnitudeBC = 1820.73lbs Problem#24.9 Determinethetensioninthecableandthehorizontalandverticalcomponentsof reactionofthepinA.ThepulleyatDisfrictionlessandthecylinderweighs80lbs. 1.)DrawtheFBD 2.)Writetheeq...
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