{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

ME 211 Homework 2 Solutions

# ME 211 Homework 2 Solutions - Problem#14.5...

This preview shows pages 1–6. Sign up to view the full content.

ME 211 Homework Set #2 Solutions 9‐19‐2008 Problem #1 – 4.5 Determine the magnitude of force at the pin A and in the cable BC needed to support the 500lb load. Neglect the weight of the boom AB. Solution 1.) Draw the Free Body Diagram (FBD) 2.) Write the equilibrium equations. Always write an equation that sums the forces in the x‐direction, a summation of the forces in the y‐direction, and a moment equation around a point where you want to eliminate an unknown. ( F x , F y , and M) M A = 0 = 8 ft * F BC *sin(13) 8 ft *500 lb *cos(35) F x = 0 = 500*sin(35) F BC *cos(13) + A X F y = 0 = 500*cos(35) + F BC *sin(13) + A y 3.) With the equations above, we now have 3 equations and 3 unknowns, so we can solve for all three unknowns (Ax, Ay, and FBC)

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
M A = 0 = 8 ft * F BC *sin(13) 8 ft *500 lb *cos(35) F BC = 1820.73 lbs F x = 0 = 500*sin(35) F BC *cos(13) + A X A X = 2060.91 lbs F y = 0 = 500*cos(35) + F BC *sin(13) + A y A y = 0 lbs 4.) With these unknowns, you can solve for the magnitude of the force at A, and the magnitude in BC is already solved for above. Magnitude A = (2060.91 2 + 0 2 = 2060.91 lbs Magnitude BC = 1820.73 lbs Answers
Problem #2 – 4.9 Determine the tension in the cable and the horizontal and vertical components of reaction of the pin A. The pulley at D is frictionless and the cylinder weighs 80lbs. 1.) Draw the FBD 2.) Write the equilibrium equations. ( F x , F y , and M) M A = 0 = T *5 ft + T *( 2 5 )*10 ft 80 lbs *13 ft F x = 0 = A X T *( 1 5 ) F y = 0 = A y + T + T *( 2 5 ) 80 lbs 3.) With the equations above, we now have 3 equations and 3 unknowns, so we can solve for all three unknowns (Ax, Ay, and T)

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
M A = 0 = T *5 ft + T *( 2 5 )*10 ft 80 lbs *13 ft T = 74.6 lbs F x = 0 = A X T *( 1 5 ) A X = 33.4 lbs F y = 0 = A y + T + T *( 2 5 ) 80 lbs A y = 61.324 lbs Answers
Problem #3 – 4.24 The crane consists of three parts, which have weights of W1 = 3500lbs, W2 = 900lbs, W3 = 1500lbs and centers of gravity at G1, G2, and G3, respectively. Neglecting the

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern