ME 211 Homework 7 Solutions

5x 8

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Unformatted text preview: T - F 8 0 = 9.60(10 ) [(200 -17.5x) - 60]dx - -6 0 8 F(8) 0 = 9.60(10 ) [(140 -17.5x)]dx - -6 0 (1.4 2 -12 )15.0(10 3 ) 4 F(8) (1.4 2 -12 )15.0(10 3 ) 4 F = 7.60kip Problem#710.56 Thesteelbolthasadiameterof7mmandfitsthroughanaluminumsleeveasshown. Thesleevehasaninnerdiameterof8mmandanouterdiameterof10mm.Thenut atAisadjustedsothatitjustpressesupagainstthesleeve.Ifitisthentightened onehalfturn,determinetheforceintheboltandthesleeve.Thesinglethreaded screwonthebolthasaleadof1.5mm.Est=200GPa,Eal=70GPa.Note:Thelead representsthedistancethenutadvancesalongtheboltforoncompleteturnofthe nut. 1.)Determinethecompatabilitycondition 0.00075 = S + b 0.00075 = F(0.1) (0.012 - 0.008 2 )70.0(10 9 ) 4 F = 11807N = 11.8kN + F(0.1) (0.007 2 )200.0(10 9 ) 4...
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This note was uploaded on 05/12/2010 for the course MECHENG 211 taught by Professor ? during the Fall '07 term at University of Michigan.

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