# 16-02-02 - n:= 1 μ =.65 μ 3 ⋅σ n =.695 μ 3 ⋅σ n...

This preview shows page 1. Sign up to view the full content.

16.2.2 A production process making chemical solutions is in control when the solution strengths have a mean of μ 0 := 0.650 and a standard deviation of σ := 0.015 Suppose that it is a reasonable approximation to take the solution strengths as being normally distributed. At regular time intervals the solution strength is measured and is plotted on a control chart. (a) What are the center line and control limits of a 3-sigma control chart that you would construct to monitor the strengths of the chemical solutions?
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: n := 1 μ = .65 μ + 3 ⋅σ n = .695 μ- 3 ⋅σ n = .605 (b) If a randomly sampled solution had a strength of x := 0.662 would you take this as evidence that the production process had moved out of control? μ- 3 ⋅σ n < x and x < μ + 3 ⋅σ n = true This value falls within the acceptable control range. What if x := 0.610 μ- 3 ⋅σ n < x and x < μ + 3 ⋅σ n = true This value falls within the acceptable control range. page 1...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online