Unformatted text preview: n := 1 μ = .65 μ + 3 ⋅σ n = .695 μ 3 ⋅σ n = .605 (b) If a randomly sampled solution had a strength of x := 0.662 would you take this as evidence that the production process had moved out of control? μ 3 ⋅σ n < x and x < μ + 3 ⋅σ n = true This value falls within the acceptable control range. What if x := 0.610 μ 3 ⋅σ n < x and x < μ + 3 ⋅σ n = true This value falls within the acceptable control range. page 1...
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 Spring '07
 JosephGeunes
 Normal Distribution, Standard Deviation, acceptable control range, solution strengths

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