# SolSec 5_7 - 5 80Problems and Solution Section 5.7(5.74...

This preview shows pages 1–2. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 5- 80Problems and Solution Section 5.7 (5.74 through 5.80) 5.74A 100-kg compressor rotor has a shaft stiffness of 1.4 ×107N/m. The compressor is designed to operate at a speed of 6000 rpm. The internal damping of the rotor shaft system is measured to be ζ= 0.01. (a) If the rotor has an eccentric radius of 1 cm, what is the rotor system's critical speed? (b) Calculate the whirl amplitude at critical speed. Compare your results to those of Example 5.7.1. Solution:(a) The critical speed is the rotor's natural frequency, so !c=km=1.4"107100=374.2 rad/s =3573 rpm(b) At critical speed, r= 1, so from Equation (5.81), X=!2"=0.012 0.01( )=0.5 mSo a system with higher eccentricity and lower damping has a greater whirl amplitude (see Example 5.7.1). 5.75Redesign the rotor system of Problem 5.74 such that the whirl amplitude at critical speed is less than 1 cm by changing the mass of the rotor....
View Full Document

## This note was uploaded on 05/12/2010 for the course AEROSPACE MAE351 taught by Professor Inlee during the Fall '09 term at Korea Advanced Institute of Science and Technology.

### Page1 / 6

SolSec 5_7 - 5 80Problems and Solution Section 5.7(5.74...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online