MCB164_S2010_MT1_key

MCB164_S2010_MT1_key - Name_KEY_ MCB164 Spring 2010 Page 1...

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Name__________KEY_____________________ MCB164 Spring 2010 MCB164 FIRST MIDTERM April 20, 2010 Question Points Score 1 18 2 14 3 14 4 32 5 14 6 22 7 20 8 20 Total 150 This examination is closed book. No calculators or cell phones. There are 8 pages to this exam. Please write your name on each page of the exam . There may be more than one correct answer for a given problem. You only need to provide one answer. HAVE FUN! Page 1 of 8
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Name__________KEY_____________________ MCB164 Spring 2010 1. (18 points) List one advantage and one disadvantage for each of the following methods of mutagenesis: Possible answers are given. Other correct answers exist. A. EMS Advantages- 1. Can be used to create missense mutations that may affect a binding site or an active site of protein or enzyme. 2. May be used to find partial loss-of-function, or conditional alleles of essential genes. 3. EMS is easy to administer to organisms by soaking or feeding. Disadvantages-1. very dangerous to work with since it is a powerful mutagen. 2. Mutations caused by EMS are not linked to any marker except the phenotype they create. B. Transposon Advantages- 1. Mutations are marked genetically so that linkage of the mutant phenotype to the transposon marker can be followed during segregation analysis. 2. Genomic DNA flanking the point of insert can be cloned by plasmid rescue. 3. Useful for creating gene disruptions or null mutations. Disadvantages-1. Transposition events have limited target specificity so some gene targets might be missed. 2. May not recover mutations in essential genes. 3. Requires more manipulations than EMS (e.g. need to get rid of transposase). C. Gene knockout by homologous recombination Advantages- Can knock out any gene for which the sequence is known and find the null phentoype. Disadvantages- 1. Not possible in many organisms. 2. Can not create point mutations using this method. Page 2 of 8
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Name__________KEY_____________________ MCB164 Spring 2010 2. (14 points) Mark each statement as either T (True) or F (False): __F___ Homologous recombination is a useful tool in C. elegans to knock out expression of any gene of interest __T___ An autosomal balancer chromosome is most useful if it carries both a dominant mutation giving a visual phenotype and a recessive lethal mutation __F____ Dominant embryonic lethal mutations are easily recovered in the F1progeny of EMS mutagenized Drosphila __T___ C. elegans live as self-fertilizing hermaphrodites but they can also mate with males to give 50% male progeny __F___ RNAi is an important tool for analyzing loss of function mutations in budding yeast __T__ Saccharomyces cerevisiae can grow both diploid and haploid cell types in a cell culture __T__ Targeted gene knock-outs in budding yeast are typically made using homologous recombination 3. (14 points) Match the genotype-phenotype relationships with the best corresponding genetic interaction listed below: (Use all examples/ one answer each) A. second site noncomplementation
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MCB164_S2010_MT1_key - Name_KEY_ MCB164 Spring 2010 Page 1...

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