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Unformatted text preview: NAME: MAE 108 – Probability and Statistical Methods for Engineers  Winter 2010 Midterm # 2 February 22, 2010 50 minutes, open book, open notes, calculator allowed, no cell phones. Write your answers directly on the exam. 40 points total. (1) (10 points) Consider a random variable X . The PDF for X is given by f X ( x ) = ce 2 x , < x < ∞ and zero otherwise. (a) Find the value of c Solution: R ∞ f X ( x ) dx = 1 so c = 2. (b) Calculate P ( X > 2). Solution: P ( X > 2) = R ∞ 2 2 e 2 x dx = [ e 2 x ] ∞ 2 = e 4 ≈ 1 . 83% (c) Calculate the mean E ( X ) Solution: E ( X ) = R ∞ 2 xe 2 x dx = 1 2 R ∞ ue u du = 1 2 by integration by parts (d) Calculate the standard deviation σ X . Solution: E ( X 2 ) = R ∞ 2 x 2 e 2 x dx = 1 4 R ∞ u 2 e u du = 1 2 by integration by parts so σ X = p E ( X 2 ) E ( X ) 2 = q 1 2 1 4 = 1 2 (2) (10 points) The SAT mathematics test scores across the population of high school seniors follow a normal distribution with mean 500 and standard deviation 100. If five seniors are randomly chosen, finddistribution with mean 500 and standard deviation 100....
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This note was uploaded on 05/12/2010 for the course MAE 108 taught by Professor Lauga during the Winter '10 term at San Diego.
 Winter '10
 Lauga

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