ps14b37 - Ph 111.01 PS 14b(37 Problem 1 = Walker P 17-26 A...

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Ph 111.01 December 10, 2008 PS 14b (37) n, T, V R A Problem 1 = Walker P. 17-26. A 390 mL spherical flask contains 0.075 mol of an ideal gas at a temperature of 237 K. What is the average force exerted on the walls of the flask by a single molecule? N Solution. From the volume we can get the radius of the sphere: () 1 1 3 3 63 3 390 10 3 0.0453 m 44 xm V R ππ ⎛⎞ ⎜⎟ = = = ⎝⎠ 3 4 3 VR π =→ And from R we can calculate the area: 2 22 A=4 R 4 0.0453 m 0.0258 m == Now, we can easily calculate the pressure per molecule from the ideal-gas equation of state in the form PV NkT = The pressure per molecule is thus 23 18 1.38 10 J/K 237 8.386 10 Pa/molecule 390 10 xK T x = Pk NV And, multiplying by the area, ( ) 18 2 19 8.386 10 Pa/molecule 0.0258 m 2.164 10 N/molecule Ax x −− = F L 0 Δ L d FP NN Problem 2 = Walker P. 17-27. A rock climber hangs freely from a nylon rope that is 12 m long and has a diameter of 6.7 mm. If the rope stretches 6.4 cm, what is the mass of the climber? kg Solution. The stretch of the rope is related to the stress by 0 L Am g L Δ FY Solving for the mass m, we find
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This note was uploaded on 05/13/2010 for the course PHYSICS 111 taught by Professor Staff during the Fall '08 term at S.F. State.

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ps14b37 - Ph 111.01 PS 14b(37 Problem 1 = Walker P 17-26 A...

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