Unformatted text preview: / s) 2 (9 . 8 m / s 2 ) sin 32 . ◦ ´ = − 1 . 18 m . (b) The time is t = − v a = − v g sin θ = − − 3 . 50 m / s (9 . 8 m / s 2 ) sin 32 . ◦ = 0 . 674 s . (c) Now set x = 0 and solve x = v t + 1 2 at 2 for t . The result is t = − 2 v a = − 2 v g sin θ = − 2( − 3 . 50 m / s) (9 . 8 m / s 2 ) sin 32 . ◦ = 1 . 35 s . The velocity is v = v + at = v + gt sin θ = − 3 . 50 m / s + (9 . 8 m / s 2 )(1 . 35 s) sin 32 ◦ = 3 . 50 m / s , as expected since there is no friction. The velocity is down the plane....
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This note was uploaded on 05/13/2010 for the course PHYSICS 12121 taught by Professor Bill during the Winter '01 term at CSU Channel Islands.
 Winter '01
 Bill
 Physics, Acceleration, Force, Gravity

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