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Unformatted text preview: θ − T 1 = 0 and the y component is T 2 sin θ − W A = 0. Eliminate the tension forces and find expressions for f and F N in terms of W A and W B , then select W A so f = µ s F N . The second Newton’s law equation gives F N = W B immediately. The third gives T 2 = T 1 / cos θ . Substitute this expression into the fourth equation to obtain T 1 = W A / tan θ . Substitute W A / tan θ for T 1 in the first equation to obtain f = W A / tan θ . For the blocks to remain stationary f must be less than µ s F N or W A / tan θ < µ s W B . The greatest that W A can be is the value for which W A / tan θ = µ s W B . Solve for W A : W A = µ s W B tan θ = (0 . 25)(711 N) tan 30 ◦ = 1 . × 10 2 N ....
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This note was uploaded on 05/13/2010 for the course PHYSICS 12121 taught by Professor Bill during the Winter '01 term at CSU Channel Islands.
 Winter '01
 Bill
 Physics, Force

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