Unformatted text preview: = mv 2 /R cos θ and when this is substituted into the second, ( mv 2 /R ) tan θ = mg results. Solve for R : R = v 2 g tan θ . The speed of the plane is v = 480 km / h = 133 m / s, so R = (133 m / s) 2 9 . 8 m / s 2 tan 50 ◦ = 2 . 2 × 10 3 m . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . • F mg θ x y...
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This note was uploaded on 05/13/2010 for the course PHYSICS 12121 taught by Professor Bill during the Winter '01 term at CSU Channel Islands.
 Winter '01
 Bill
 Physics, Force, Mass

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