Chapter 10, Problem 16 (1) - A disk rotates about its...

Info icon This preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: A disk rotates about its central axis starting from rest and accelerates with constant angular acceleration. At one time it is rotating at 9.6 revls; 92 revolutions later, its angular speed is 22 revi's. Calculate {a} the angular acceleration (revis‘2), {b} the time required to complete the 92 revolutions, {c} the time required to reach the 9.6 revr's angular speed, and {d} the number of revolutions from rest until the time the disk reaches the 9.6 revls angular speed. Given Initial angular velocity uJa : 9.3 revisec = 9.6*2*pi radianfsec = 33.32 radl's Final ang. velocity l—lul :1 22 revfs = 22*2*pi radfs = 138.23 radfs Angular displacement G I 92 rev = 92*2*pi radians = 5?8.1 rad. ,,_ '1 muse lo :- UJu +1016 A 1. Angular acceleration Thus, (13823)"? = (68.32)”? + 2*alpha*5?8.1 Or alpha = 13.38 radfs“2 = 2.13 revfs“2 (b)Use VJ:LJ*J'{J_l’-D<-t Or i a ULL‘JEL 13323—3332 04 13.33 2 fl'2 5.82 sec 13.33 (c)oJa=U / l 3 _ Ct . lo MW (5 :6032 radils t=4.508221226 sec (d) Ldo '— O -t_ :4533 s and —_ 13.33 radfs“2 ’l_ U53 (5‘: lJ—lrJJDJf-lifit : O—l— Jidf I a 2. .- 711333 (453332 = M 1 135.95 _§______ iii ...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern