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TA C162 - BIRLA INSTITUTE OF TECHNOLOGY AND SCIENCE PILANI...

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BIRLA INSTITUTE OF TECHNOLOGY AND SCIENCE, PILANI – 333031 Second Semester 2004-2005 TA C162 Computer Programming-I Comprehensive Examination (CLOSED BOOK) 30% (90 Marks) May 09, 2005 (08-11 AM) ID.No. _____________________ Instructions: [1] The question paper contains two parts, namely Part A and Part B , with maximum marks 50 and 40 respectively. Each part has to be answered in separate answer-sheet. Part A has to be completed within first 75 minutes . You can attempt Part B after submission (immediately after 75 minutes or earlier) of Part A. [2] Avoid overwriting. [3] Calculators are not allowed. Part A MM=50 Time= 75 Mins. For each question select the most appropriate choice among the four choices given and put a tick ( ) mark corresponding to the selected choice in the given answer-sheet. Each correct answer fetches 2 marks . There is no negative marking for Part A. What will be the output of the following C programs or program segments given in question to 1 to 9? Assume that required header and library files are included. Q1. main() { int x,y;x=y=0; while(y<10) ++y; x+=y; printf("x=%d,y=%d",x,y); } A. x=10,y=10 B. x=10,y=9 C. x=9,y=10 D. x=11, y=11 Q2. main() { int a[10]; i=10; for(i=0;i<5;i++) a[i]=0; for(i=0;i<=5;i++) a[i]=i++; for(i=0;i<=5;i++) printf("%d ",a[i]); } A. 1 2 3 4 5 6 B. 0 0 2 0 4 0 C. 1 0 2 0 3 4 D. 0 0 0 0 0 0 Q3. main() {void change(int); int a=4; change(a); printf("%d",a); } void change(int a) { printf("%d" ,++a); } Q4. main() { int i=6720,j=4; while((i%j)==0) { i=i/j;j=j+1;} printf("%d",j); }
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