Chapter 2 Checkpoint Basic Math

# Chapter 2 - Name Paula Lewis Date CheckPoint Chapter 2 Section 2.1 2.1 2.1 Page 122 122 122 Please put your work and answer in this column Credit

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Name: Paula Lewis Date: April 20, 2010 CheckPoint: Chapter 2 Section Page # Please put your work and answer in this column . Credit Earned Correct answer if incorrect 2.1 122 #10   1, 2, 3, 6, 11, 22, 33, and 66     2.1 122 #14 15, 55, 91, and 105   2.1 122 #16 59, 61, 67, 71, and 73   2.1 123 #22 Get the factors of 80: 80 = 10*8 = 5*2*8 = 5*2*2*2*2 He can't do groups of 6, since there is no factor of 3. He can do groups of 10, since 10 = 5*2. He can do 8, since 8 = 2*2*2, and we have those factors.   2.2 131 #20 2*3*5*11   2.2 131 #24 7 and 4   2.2 132 #42 36=1,2,3,4,6,9,12,18,36 72=1,2,3,4,6,8,9,12,18,24,36,72 144=1,2,3,4,6,8,9,12,16,18,24,36, 48,72,144 GFC= 36   2.3 142 #8 3 4   2.3 143 #18 5 9   2.3 144 #42 58/7 8 r2 8 2/7   2.3 144 #60 13 2/5 = 13*(5/5) + 2/5 = 65/5 + 2/5 = 67/5

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2.4 153 #14 Jeff: 104/325=0.32 Matt: 88/275=0.32 same batting average   2.4 154 #30 17/51 = 1*17 / 3*17 = 1/3   2.4 154 #42 42/55 = 2 * 3 * 7 / 5 * 11 this is as simple as it gets, it remains
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## This note was uploaded on 05/14/2010 for the course CRT 220 crt 220 taught by Professor Axiacollege during the Spring '10 term at University of Phoenix.

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Chapter 2 - Name Paula Lewis Date CheckPoint Chapter 2 Section 2.1 2.1 2.1 Page 122 122 122 Please put your work and answer in this column Credit

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