BIO 325 - Fall 2009 - TTh 930 to 1100 - Quiz 3 key (1)

BIO 325 - Fall 2009 - TTh 930 to 1100 - Quiz 3 key (1) -...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
GENETICS (BIO 325) Fall 2009 T, Th 9:30 – 11:00 AM section Key - Quiz 3 __________________________________________________________________________________ 1. (a) A 6-base cutter will cleave random-sequence DNA on average once every 4 6 = 4096 nucleotides. Therefore, on average there would be 3 × 10 9 /4096 = 732,422 cleavage sites in this much DNA, and thus about 732,422 different fragments. (b) A 4-base cutter would cut, on average, once every 4 4 = 256 nucleotides. Therefore, you’d expect about 11,718,750 different fragments. 2. Using a double digest with
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Xba I and Not I would isolate the DNA of interest and allow it to be cloned into the corresponding Xba I and Not I sites of the plasmid vector. Eco RI and Hind III are not useful because they cut within the DNA of interest. Sph I is not useful because there is no corresponding Sph I site on the cloning vector. 3. Primers (a) and (h) 4. (a) False (b) True (c) True (d) True (e) False 5. (a) Genomic library (b) Genomic library (c) cDNA library (d) Genomic library (e) cDNA library...
View Full Document

This note was uploaded on 05/15/2010 for the course BIO 325 taught by Professor Saxena during the Spring '08 term at University of Texas.

Ask a homework question - tutors are online