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# hw2_soln3 - HW Set 2 Due 4/13 in quiz session HW5 hw_F hw_G...

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HW Set 2: Due 4/13 in quiz session. HW5: hw_F, hw_G, hw_H, hw_I (end of lecture 5), HW6: 2.8, 2.12, hw_J (end of lecture 6). HW7: 2.22, hw_K, hw_L (end of lecture 7), 2.39c (by computer; check homework Rules for what that means), 2.45 (make sure you compute the normal quantile plot, by hand). HW8: hw_M, hw_N, 3.12 (By hand or by computer, but EXPLAIN your answers to parts b and c) . Graded problems (and points): TBA. Hw.G Using Table III ( λ = 20), Proportion(x 15) = 1 - Proportion(x 14) = 1 - (.000 + .000+ … + .001+ .001 + .003 + .006 + .011 + .018 + .-27 + .039) = 1 - . 106 = .894. Because λ is an "average rate" (e.g., average number of knots per unit foot of lumber, or the average number of people arriving at a teller per hour), then the λ for 1-acre lots should be 4 times the λ of the quarter-acre lots, i.e. 4*20 = 80. 2.8 0 4 75 . 2 75 . ) 1 )( 75 )(. ( 1 1 4 2 1 1 2 = - = - = - - x x dx x x μ The mean value of x equals 0. 2.12 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 ( 29 64 . 2 6 6 5 5 20 . 4 25 . 3 20 . 2 15 . 1 10 . 0 ) ( 6 0 = + + + + + + = = = p p x xp x μ

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64 . 2 )) 6 ( ( 6 )) 5 ( ( 5 1 . 2 = + + p p 54 . )) 6 ( ( 6 )) 5 ( ( 5 = + p p Also, we know that = 1 ) ( x p ] [ ) 20 (. ) 25 (. ) 20 (. ) 15 (. ) 10 (. 1 ) 6 ( ) 5 ( + + + + - = + p p 10 . 90 . 1 )
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hw2_soln3 - HW Set 2 Due 4/13 in quiz session HW5 hw_F hw_G...

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