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SPSolution3-5

# SPSolution3-5 - Naik Sameer V Solution for Special Problem...

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Naik, Sameer V. Fall 2009 1000 Solution for Special Problem 3 Given: - A double U-tube connecting two horizontal pipelines - Density of sea water = 1035 kg/m 3 Find: - Pressure difference between the pipelines - Effect of air column - Effect of an oil column instead of the air column System: Assumptions: - Liquids are incompressible Basic Equation(s): atm P P gL ρ = + Solution: (a) Let the pressure in the fresh water pipeline be P 1 and the pressure in the sea water pipeline be P 5 ; the different points are as shown in the figure above. As we move along the manometer connecting the two pipelines, pressure increases when moving in the downward direction while pressure decreases when moving in the upward direction. We can write: 1 5 freshwater freshwater mercury mercury air air seawater seawater P gh gh gh gh P ρ ρ ρ ρ + + = Using Table A-19, we have: 3 kg 996 m freshwater ρ = ; 3 kg 13,529 m mercury ρ = For STP conditions: 3 kg 1.2 m air ρ = Sea Water Mercury Air 60 cm 10 cm 70 cm 40 cm 1 2 3 4 5 Fresh Water

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